Nilai dari 2log8-2log0,25+2log1 adalah

SIfat Logaritma:
ᵃlog a = 1
ᵃlog b + ᵃlog c = ᵃlog(b.c)
ᵃlog b - ᵃlog c = ᵃlog(b/c)

==Jawaban==
²log 8 - ²log 0,25 + ²log 1
= ²log(8/0,25) + ²log 1
= ²log 32 + ²log 1
= ²log(32.1)
= ²log 32
= ²log 2⁵
= 5.²log 2
= 5.1
= 5