yg bisa tolong dong:( aku ga ngerti nih

1) f(x) = (2x + 1) / (x - 3) . ≠ 3

y = (2x + 1) / (x - 3)

kali silang

y(x - 3) = 2x + 1
xy - 3y = 2x + 1
xy - 2x = 3y + 1
x (y - 2) = 3y + 1
x = (3y + 1) / (y - 2)
f-¹(x) = (3x + 1) / (x - 2) ≠ 2

f-¹(3) = (3(3) + 1) / (3 - 2)
f-¹(3) = 10 / 1
f-¹(3) = 10

2) f(x) = (4x + 5) / (x + 3)
y = (4x + 5) / (x + 3)
y(x + 3) = 4x + 5
xy + 3y = 4x + 5
xy - 4x = 5 - 3y
x (y - 4) = 5 - 3y
f-¹(x) = (5 - 3x) / (x - 4)
atau
f-¹(x) = (-3x + 5) / (x - 4) , ≠4

3) f(x) = 2x + 3
dan g(x) = (x - 1) / (x + 5) , ≠ 5
(f o g) (x) = f (g(x))
(f o g) (x) = (5x + 13) / (x + 5)
cara nya

[tex]2 (\frac{x - 1}{ x + 5}) + 3 \\ \frac{2x - 1}{x + 5} + 3 \\ \frac{2x - 2 + 3x + 15}{x + 5} \\ \frac{5x + 13}{x + 5} [/tex]
4) dalam satuan derajat
a) ½π = 90°
b) ¾π = ¾ × 180° = 270°
c) 5/4 π = 5/4 × 180° = 225°