Turunan dari : F(x)= [tex] \frac{2 { { {x}^{2} } + 3x{} } {} }{5x + 1} [/tex]
Matematika
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Pertanyaan
Turunan dari :
F(x)= [tex] \frac{2 { { {x}^{2} } + 3x{} } {} }{5x + 1} [/tex]
F(x)= [tex] \frac{2 { { {x}^{2} } + 3x{} } {} }{5x + 1} [/tex]
1 Jawaban
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1. Jawaban Anonyme
Kelas 11 Matematika
Bab Turunan
f(x) = (2x² + 3x)/(5x + 1)
u = 2x² + 3x
u' = 4x + 3
v = 5x + 1
v' = 5
f' (x) = (u' v - u v')/v²
f' (x) = ((4x + 3) . (5x + 1) - (2x² + 3x) . 5)/(5x + 1)²
f' (x) = (20x² + 4x + 15x + 3 - 10x² - 15x)/(5x + 1)²
f' (x) = (10x² + 4x + 3)/(5x² + 10x + 1)