Matematika

Pertanyaan

Nilai dari ³log81+³log81-³log27 = ......

2 Jawaban

  • Materi : Logaritma
    Kelas : X SMA

    ^3 log81 + ^3 log81 - ^3 log27
    》4 + 4 - 3
    》8 - 3
    》5
  • SIfat Logaritma:
    ᵃlog a = 1
    ᵃlog b + ᵃlog c = ᵃlog(b.c)
    ᵃlog b - ᵃlog c = ᵃlog(b/c)

    ==Jawaban==
    ³log81 + ³log81 - ³log27
    ³log(81.81) - ³log27
    = ³log6561 - ³log27
    = ³log(6561/27)
    = ³log243
    = ³log3⁵
    = 5.³log3
    = 5.1
    = 5

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