tolong dibantu soal ini saya kesulitan

[tex] {f}^{ - 1} = \frac{5x + 3}{2x - 1} \\ y(2x - 1) = 5x + 3 \\ 2xy - y = 5x + 3 \\ 2xy - 5x = y + 3 \\ x(2y - 5) = y + 3 \\ x = \frac{y + 3}{2y - 5} \\ {f}^{ - 1} = \frac{x + 3}{2x - 5}[/tex]

[tex] {g}^{ - 1} = 3x + 2 \\ y = 3x + 2 \\ - 3x = - y + 2 \\ x = \frac{y - 2}{3} \\ {g}^{ - 1} = \frac{x - 2}{3} [/tex]

[tex]a. \\ ( {f}^{ - 1} o \: g)(x) \\ = \frac{(3x + 2) + 3}{2(3x + 2) - 5} \\ = \frac{3x + 5}{6x + 4 - 5} \\ = \frac{3x + 5}{6x - 1} [/tex]

[tex]b. \\ (f \: o \: {g}^{ - 1} )(x) \\ = \frac{5(\frac{x - 2}{3} )+ 3}{2( \frac{x - 2}{3} )- 1} \times \frac{3}{3} \\ = \frac{5(x - 2) + 9}{2(x - 2) - 3} \\ = \frac{5x - 10 + 9}{2x - 4 - 3} \\ = \frac{5x - 1}{2x - 7} [/tex]

[tex]c. \\ ( {f}^{ - 1} \: o \: {g}^{ - 1} )(x) \\ = \frac{(\frac{x - 2}{3} ) + 3}{2(\frac{x - 2}{3} ) - 5} \times \frac{3}{3} \\ = \frac{(x - 2) + 9}{2( x - 2) - 15} \\ = \frac{x - 2 + 9}{2x - 4 - 15} \\ = \frac{x + 7}{2x - 19} [/tex]
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