Tentukan basil operasi bilangan (√6+6)²?

[tex]( \sqrt{6} + 6)^{2} = ( \sqrt{6} )^{2} + 2( \sqrt{6} ) (6) + {6}^{2} \\ = 6 + 12 \sqrt{6} + 36 \\ = 42 + 12 \sqrt{6} = \\ = 6(7 + 2 \sqrt{2} )[/tex]