(tolong isi cara) p.s may god bless you

Kelas 8 Matematika
Bab Persamaan Garis

(-4, 3) dan (0,6)

(y - y1)/(y2 - y1) = (x - x1)/(x2 - x1)
(y - 3)/(6 - 3) = (x - (-4))/(0 - (-4))
(y - 3)/3 = (x + 4)/(4
4(y - 3) = 3(x + 4)
4y - 12 = 3x + 12
4y = 3x + 12 + 12
y = (3/4) x + (24/4)
y = (3/4) x + 6