tolong:( bantu besok ulangan nih:(

5) √75 + 2√12 - √27
= √(25) . 3 + 2√(4) . 3 - √(9) . 3
= 5√3 + 2(2)√3 - 3√3
= 5√3 + 4√3 - 3√3
= (5 + 4 - 3) √3
= 6√3 (e)

6) p = 3√5 + 2√3 dan q = 3√5 - 2√3
ditanyakan p² - 2pq + q²
p² - 2pq + q² = (p - q) (p - q)
p² - 2pq + q² = (p - q)²
p² - 2pq + q² = ( (3√5 + 2√3 - 3√5 + 2√3)
p² - 2pq + q² = 4√3
(a)

7) luas segitiga siku siku = ( s1 × s2 ) / 2
[tex]l = \frac{s1 \times \: s2 }{2} \\ s2 = \frac{2l}{s1} \\ s2 = \frac{2(3 + 8 \sqrt{2} )}{(2 + 3 \sqrt{2}) } \\ s2 = \frac{6 + 16 \sqrt{2} }{(2 + 3 \sqrt{2}) } \times \frac{2 - 3 \sqrt{2} }{2 - 3 \sqrt{2} } \\ s2 = \frac{(12 - 18 \sqrt{2} + 32 \sqrt{2} - 96 }{4 - 18} \\ s2 = \frac{ - 84 + 14 \sqrt{2} }{ - 14} \\ s2 = 6 - \sqrt{2} [/tex]

maka panjang sisi siku siku segitiga yang lain adalah = 6 - √2

8)
[tex] \sqrt[5]{ \frac{4}{ {2}^{ \: 3 - x} } } = \frac{1}{32} \\ \frac{4}{ {2}^{3 - x} } = { (\frac{1}{32}) }^{5} \\ \frac{ {2}^{2} }{ {2}^{3} \: {2}^{ - x} } = {( {2}^{ - 5}) }^{5} \\ { 2 }^{ - 1} \: {2}^{x} = {2}^{ - 25} \\ {2}^{ - 1 + x} = {2}^{ - 25} [/tex]
karena basis sudah sama sehingga diperoleh
hanya hitung pangkatnya
-1 + x = -25
x = -25 + 1
x = -24

9) ³log 81 + ³log 81 - ³log 27
= ³log (3)⁴ + ³log (3)⁴ - ³log (3)³
= 4 ³log 3 + 4 ³log 3 - 3 ³log 3
= 4 (1) + 4(1) - 3(1)
= 8 - 3
= 5