tentukan panjang AC dan AD

Panjang
AC =
[tex] \sqrt{ {9}^{2} + {12}^{2} } \\ = \sqrt{81 + 144} \\ = \sqrt{225} \\ = 15[/tex]
Panjang AD
[tex] \frac{ad}{ab} = \frac{ac}{dc} \\ \frac{12}{15} = \frac{ac}{25} \\ \frac{4}{5} = \frac{ac}{25} \\ 25 \times 4 = 5 \times ac \\ 100 = 5ac \\ ac = \frac{100}{5} \\ ac = 20[/tex]