Tentukan akar-akar persamaan kuadrat dari x²-11x+23=0. Dengan cara melengkapkan kuadrat sempurna. Tolongin ya teman..

[tex]\text{\hspace{13mm}}x^{2}-11x+23 & =0\\ \\ x^{2}-11x+\left(\frac{11}{2}\right)^{2}+23=\left(\frac{11}{2}\right)^{2}\\ \\ \text{\hspace{11mm}}x^{2}-11x+\frac{121}{4} & =\frac{121}{4}-23\\ \\ \text{\hspace{6mm}}\left(x-\frac{11}{2}\right)\left(x-\frac{11}{2}\right) & =\frac{29}{4}\\ \\ \text{\hspace{18mm}}\left(x-\frac{11}{2}\right)^{2} & =\frac{29}{4}\\ \\ \text{\hspace{23mm}}x-\frac{11}{2} & =\pm\sqrt{\frac{29}{4}}\\ \\ \text{\hspace{31mm}}x & =\frac{11}{2}\pm\frac{\sqrt{29}}{2}[/tex]