Standar deviasi dari data 11,8,6,3,2 adalah...

Diketahui [tex]n=5[/tex], rata-rat:

[tex]\mu=\frac{11+8+6+3+2}{5} \\ \text{\hspace{2mm}}=\frac{30}{5} \\\text{\hspace{2mm}} =6[/tex]

Rumus standar deviasi adalah:

[tex]std=\sqrt{\frac{1}{n}\sum_{i=1}^{n}\left(x_{i}-\mu\right)^{2}}[/tex]

Maka:

[tex]std & =\sqrt{\frac{\left(11-6\right)^{2}+\left(8-6\right)^{2}+\left(6-6\right)^{2}+\left(3-6\right)^{2}+\left(2-6\right)^{2}}{5}}\\ \text{\hspace{4mm}}=\sqrt{\frac{5^{2}+2^{2}+0^{2}+\left(-3\right)^{2}+\left(-4\right)^{2}}{5}}\\ \text{\hspace{4mm}}& =\sqrt{\frac{25+4+9+16}{5}}\\ \text{\hspace{4mm}} & =\sqrt{\frac{54}{5}}\\ \text{\hspace{4mm}} & =3.286335345[/tex]