5log9 + 5log2 - 5log 450 = ...

Kelas 10 Matematika
Bab Logaritma

^ = pangkat

^5log 9 + ^5log 2 - ^5log 450
= ^5log (9 . 2/450)
= ^5log (18/450)
= ^5log (1/25)
= ^5log 5^(-2)
= -2 . ^5log 5
= -2

5log9 + 5log2 - 5log450
[tex]^{5}log9 + ^{5}log2 - ^{5}log450 \\ = \: ^{5} log( \frac{9 \times 2}{450} ) \\ = \: ^{5} log(0.04) \\ = \: ^{5}log(4 \times {10}^{ - 2} )[/tex]
Maksud pertanyaannya begitu, kan?