Himpunan penyelesaian persamaan |8-4x|=|x-5| adalah {p,q}. nilai p+3q

|8-4x|=|x-5|, buat ilangin tanda mutlaknya kedua ruas dipangkat 2 jadi,
|8-4x|²=|x-5|²
=> (8-4x)² = (x-5)²
=> 64 - 64x + 16x² = x² - 10x + 25
=> 16x²-x²-64x+10x+64-25 = 0
=> 15x²-54x+39 = 0
=> (x - 1) (5x - 13)
=> x = 1 x = 13/5

x = 1 = p, x = 13/5 = q, maka
p + 3q = 1 + 3(13/5) = 1 + 39/5 = 44/5 = 8 4/5