Matematika

Pertanyaan

HP penyelesaian persamaan
{x+y+z=2
2x-y+z=-1
x-y-z=0

1 Jawaban

  • x+y+z =2
    2x-y+z =-1
    __________-
    -x +2y = 3

    2x-y+z=-1
    x-y-z = 0
    _________+
    3x - 2y = - 1

    -x+2y = 3
    3x-2y = - 1
    ___________+
    2x = 2
    x = 1

    3x - 2y = - 1
    3(1)-2y = - 1
    -2y = - 1 - 3
    -2y = - 4
    y = 2

    x-y-z = 0
    1-2-z =0
    -1-z = 0
    -z = 1
    z= - 1

    (x, y dan z = 1,2 dan - 1)

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