Tentukan nilai x,y,dan z dari persamaan 2x+3y-z = 20; 3x+2y+z = 20; x+4y+2z= 15? tolong dijawab dgn caranya yaa

2x+3y-z = 20
3x+2y+z = 20
__________ +
z = 0

2x + 3y - (0) = 20
2x + 3y = 20

x + 4y + 2z = 15
x + 4y + 2(0) = 15
x + 4y = 15

2x + 3y = 20| x1
x + 4y = 15 | x2
_____________
2x + 3y = 20
2x + 8y = 30
__________ -
- 5y = - 10
y = 2

2x + 3y = 20
2x + 3(2) = 20
2x + 6 = 20
2x = 14
x = 7

3x + 2y + z = 20
3(7) + 2(2) + z = 20
21 + 4 + z = 20
25 + z = 20
z = 20 - 25
z = - 5

Hp : {7, 2, -5}