1.Nilai mutlak |x+1|=3 A.2,4,-5 B.2,4 C.-2,-4 D.4,-2 2.himpunan penyelesaian |x+1|=2x-5

1.
| x + 1 | = 3

x + 1 = -3
x = -4

x + 1 = 3
x = 2

HP = {2 , -4}

2.
| x + 1 | = 2x - 5

x + 1 = 2x - 5
x = 6

x + 1 = -2x + 5
3x = 4
x = 4/3

HP = {4/3 , 6}