nilai dari 2 logc32+3log 27-4log 16

[tex]^2\log(32)+^3\log(27)-^4\log(16)=\cdots \\ \\ =\,^2\log(2^5)+\,^3\log(3^3)-\,^4\log(4^2) \\ \\ =\,5\times\,^2\log(2)+3\times\,^3\log(3)-2\times\,^4\log(4) \\ \\ =5+3-2 \\ \\ =6[/tex]