persamaan garis yang melalui titik (4,1) dan (6,-2)

[tex] \frac{y - y1}{y2 - y1} = \frac{x - x1}{x2 - x1} \\ \frac{y - 1}{ - 2 - 1} = \frac{x - 4}{6 - 4} \\ \frac{y - 1}{ - 3} = \frac{x - 4}{2} \\ 2(y - 1) = - 3(x - 4) \\ 2y - 2 = - 3x + 12 \\ 3x + 2y - 14 = 0 \\ 3x + 2y = 14[/tex]