2log3=x 7log3=y maka 14log63=

^2 log3 = x
^7 log3 = y

berarti,
^3 log7 = 1/y

^2 log7 = ^2 log3 . ^3 log7
= x. 1/y
= x/y

^14 log63 = ^2 log63 / ^2 log14
= ^2 log3^2 . ^2 log7 / ^2 log7 . ^2 log2
= 2. ^2 log3 . ^2 log7 / ^2 log7 . 1
= 2x. x/y / x/y
= 2x