Tentukan penyelesaian persamaan nilai mutlak |4x+7|=|2x-1|

|4x+7=2x-1|
4x-2x=-1-7
2x=-8
x=-8/2
x=-4

|4x+7|=-|2x-1|
4x+7=-2x+1
4x+2x=1-7
6x=-6
x=-6/6
x=-1

jadi, HP {-4, -1}

|4x+7|=|2x-1|
(4x + 7)² = (2x - 1)²
16x² + 56x + 49 = 4x² - 4x + 1
12x² + 60x + 48 = 0
x² + 5x + 4 = 0
(x + 4) (x + 1) = 0
x = -4  atau  x = -1

HP = {-4 , -1}