Matematika

Pertanyaan

Jika ³log 5=p nilai 9 log 15=....

2 Jawaban

  • ³log5 = p

    ⁹log15
    = (3²)log(3 . 5)
    = (1/2) ³log(3 . 5)
    = (1/2) . [³log3 + ³log5]
    = (1/2) . [1 + p]
    = (1 + p) / 2
  • Jawabannya:
    ³log5= p
    nilai 9log15
    (3²)
    =(1/2)log(3.5)
    =(1/2).(3log3+3log5)
    =(1/2).(1+p)
    =(1+p)/2

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