bila X1 dan X2 akar-akar persamaan kuadrat 3x kuadrat 2-2x-8=0 maka nilai dari 1/X1+1/X2=

3x²-2x-8 = 0
(3x+4)(x-2) = 0
x1 = -4/3
x2 = 2

1/x1 + 1/x2 = 1/-4/3 + 1/2 = -3/4+2/4 = -1/4

Ada cara cepat juga :
x1 + x2 = -b/a = -(-2)/3 = 2/3
x1x2 = c/a = -8/3

1/x1 + 1/x2 = x1+x2/x1x2 = 2/3 / -8/3 = -2/8 = -1/4

Maaf jika ad kesalahan :)