x2-3y2=-23 dan 2x2-4y2=-14 nilai 2q2-p2
Matematika
vikkysimbolon03
Pertanyaan
x2-3y2=-23 dan 2x2-4y2=-14 nilai 2q2-p2
1 Jawaban
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1. Jawaban msvioland
[tex] {x}^{2} - 3 {y}^{2} = - 23 \\ 2 {x}^{2} - 4 {y}^{2} = - 14 \\ kalikan \: persamaan \: pertama \: dengan \: bilangan \: 2 \\ 2 {x}^{2} - 6 {y}^{2} = - 46 \\ 2 {x}^{2} - 4 {y}^{2} = - 14 \\ kurangkan \: persamaan \: diatas \\ - 2 {y}^{2} = - 32 \\ {y}^{2} = \frac{32}{2} \\ {y}^{2} = 16 \\ y = \sqrt{16} \\ y = 4 \\ substitusikan \: nilai \: y \: ke \: persamaan \: pertama \\ {x}^{2} - 3 {y}^{2} = - 23 \\ {x}^{2} - 3( {4}^{2} ) = - 23 \\ {x}^{2} = - 23 + 48 \\ {x}^{2} = 25 \\ x = \sqrt{25} \\ x = 5 \\ \\ jadi \: untuk \: nilai \\ \: 2 {y}^{2} - {x}^{2} = 2( {4})^{2} - ( {5})^{2} \\ = 2(16) - 25 \\ = 32 - 25 \\ = 7[/tex]