Matematika

Pertanyaan

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tolong tolong tolong tolong

2 Jawaban


  • [tex] |2x - 1| < x + 1 \\ 2x - 1 - x < 1, \: 2x - 1 \geqslant 0 \\ - (2x - 1) - x < 1, 2x - 1 < 0 \\ x < 2, x \geqslant \frac{1}{2} \\ x > 0, x < \frac{1}{2} \\ yg \: d \: jawabannya[/tex]
  • -(x+1) < 2x - 1 < x + 1

    -x - 1 < 2x - 1
    -x - 2x < -1 + 1
    -3x < 0
    x > 0/-3
    x > 0

    2x - 1 < x + 1
    2x - x < 1 + 1
    x < 2

    0 < x < 2