Matematika

Pertanyaan

akar 27 dikurangi akar 75 dikali akar 16 ditambah akar 2 dikali akar 6

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  • [tex] \sqrt{27} - \sqrt{75} \times \sqrt{16} + \sqrt{2} \times \sqrt{6} \\ = \sqrt{3 \times 9} - \sqrt{3 \times 25} \times 4 + \sqrt{2} \times \sqrt{6} \\ = 3 \sqrt{3} - 5 \sqrt{3} \times 4 + \sqrt{2} \times \sqrt{6} \\ = 3 \sqrt{3} - 20 \sqrt{3} + \sqrt{12} \\ = - 17 \sqrt{3} + \sqrt{3 \times 4} \\ = - 17 \sqrt{3} + 2 \sqrt{3} \\ = - 15 \sqrt{3} [/tex]

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